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php怎么解析出多维的json?

$json=' {"name":"HBuilder","email":"hhhh@163.com","data":[{"name":"aaa","email":"aaaa@163.com","password":"kjkdsjfksd"},{"name":"bbb","email":"bbbb@163.com","password":"bbbb"}]}'$obj = json_decode($json);$data=$obj['data'];prin...

$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUCCESS"}}';$arr = json_decode($jsonStr, true);$payzt = $arr['msg']['payzt'];// 或者$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUC...

php中将数组格式换换为json格式可以使用 json_encode函数。 示例代码如下: json格式效果:

//使用json_decode函数解码 $arr = json_decode($json,true); $number = $arr['number'];

//使用json_decode函数解码$arr = json_decode($json,true);$number = $arr['number'];

这个是转义而已啊! 如果你真的用ajax 输出到前台转成 json 对象的话反斜杠是不会有的! 而且你自己拼装你想要的json字符串肯定也要转义的!

//数据库连接自己写$Rult = mysql_query('你的Sql语句');while( $row = mysql_fetch_assoc( $Rult ) ){ $Data[] = $row;} $Json['array'] = $Data;echo json_encode( $Json );//没有测试, 大致思路是这样

$jsonStr = '[{"text":"感觉Onedrive图片加载的速度特别慢","created":"Sat Nov 07 20:47:13 +0000 2015","favorite_count":0,"retweet_count":0,"url":"","media_url":""}]';$arr = json_decode($jsonStr, true);$text = $arr['text'];$created...

将json转化为数组, 再对数组进行取值

print_r($obj->taobaoke_items_get_response->taobaoke_items->taobaoke_item)

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