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如何用php解一个多层嵌套的json啊

就$data['data'][0]['province']这样呗。

php解析多层 json嵌套 for ($i = 0; $i < $count_json2; $i++) { $title = $de_json2[0]['result']['data'][0]['title']; $imtro = $de_json2[0]['result']['data'][0]['imtro']; $stepsimg1 = $de_json2[0]['result']['data'][0]['steps'][0]['...

你这个json转过来还是对象,直接转成数组就好取值了。 $arr = json_decode($str,1); // $str 代表json字符串 转成数组就可以随便取值了。 $lat = $arr['content']['location']['lat']; $ing= $arr['content']['location']['ing'];

$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUCCESS"}}';$arr = json_decode($jsonStr, true);$payzt = $arr['msg']['payzt'];// 或者$jsonStr = '{"msg":{"auth":"Yes_auth","ddid":"1","payje":0.3,"payzt":"SUC...

$obj_array = json_decode($result); $r_array = object_array($obj_array); print_r($r_array ); function object_array($obj_array){ if(is_object($obj_array)){ $obj_array = (array)$obj_array; } if(is_array($obj_array)){ foreach($obj_...

比如上图中那个数组的名字是$data['results'] = xxxxx;的 后台直接调用echo json_encode($data['results']);exit;就可以直接把数组变成JSON对象,并且顺序和数组的原始顺序一样

$json=' {"name":"HBuilder","email":"hhhh@163.com","data":[{"name":"aaa","email":"aaaa@163.com","password":"kjkdsjfksd"},{"name":"bbb","email":"bbbb@163.com","password":"bbbb"}]}'$obj = json_decode($json);$data=$obj['data'];prin...

假设你上面两个json分别赋值给变量 $json1 和 $json2 $newJson = json_encode( array_merge( json_decode($json1, true), array('shangpuSP' => json_decode($json2, true) ) ) );

$jsonStr = '[{"text":"感觉Onedrive图片加载的速度特别慢","created":"Sat Nov 07 20:47:13 +0000 2015","favorite_count":0,"retweet_count":0,"url":"","media_url":""}]';$arr = json_decode($jsonStr, true);$text = $arr['text'];$created...

如果你是PHP程序里面提交的话,你可以用CURL,post方式来实现

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